Asked by JOSH
A 25 kg box is along a horizontal floor and a force of 400 N pushes the box with an angle of 50 deg with the horizontal. Starting from rest, the box achieves a velocity of 2 m/s in a time of 4 seconds. Find the coefficient of sliding friction between box and the floor.
Answers
Answered by
bobpursley
break the pushing force into vertical and horizonal components, Fv, Fh
Fv=400sin50
Fh=400cos50
Now, write the force equation
forcetotal=ma
fh-mu*(mg+Fv)=ma solve for mu, knowing acceleration is frdom
a=changevelocity/time=2/4 m/s^2=.5m/s^2
Fv=400sin50
Fh=400cos50
Now, write the force equation
forcetotal=ma
fh-mu*(mg+Fv)=ma solve for mu, knowing acceleration is frdom
a=changevelocity/time=2/4 m/s^2=.5m/s^2
Answered by
Ez
I am handsome
Answered by
Nhadii
What would be the weight of the box?
Answered by
Nhadii
If it were not given
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