Question
A 25 kg box is along a horizontal floor and a force of 400 N pushes the box with an angle of 50 deg with the horizontal. Starting from rest, the box achieves a velocity of 2 m/s in a time of 4 seconds. Find the coefficient of sliding friction between box and the floor.
Answers
bobpursley
break the pushing force into vertical and horizonal components, Fv, Fh
Fv=400sin50
Fh=400cos50
Now, write the force equation
forcetotal=ma
fh-mu*(mg+Fv)=ma solve for mu, knowing acceleration is frdom
a=changevelocity/time=2/4 m/s^2=.5m/s^2
Fv=400sin50
Fh=400cos50
Now, write the force equation
forcetotal=ma
fh-mu*(mg+Fv)=ma solve for mu, knowing acceleration is frdom
a=changevelocity/time=2/4 m/s^2=.5m/s^2
I am handsome
What would be the weight of the box?
If it were not given
Related Questions
Madison pushes with a 160-N horizontal force on a 20-kg crate of coffee resting on a warehouse floor...
A box which has a mass of 90.8kg is at rest on a rough horizontal floor, A man pushes on the box wit...
A box which has a mass of 90.8kg is at rest on a rough horizontal floor, A man pushes on the box wit...
A horizontal force of magnitude 23.1 N pushes a box along a horizontal floor at a constant speed of...