Asked by Sahil Khan
An air balloon is at rest in the air and a stone is dropped from it.
It passes a 81m tower in quarter of a second and comes on the ground.
Find the final velocity and the height of the air balloon.
It passes a 81m tower in quarter of a second and comes on the ground.
Find the final velocity and the height of the air balloon.
Answers
Answered by
Henry
d = 0.5g*t^2 = ho-81
4.9*0.25^2 = ho-81
0.306 = ho-81
ho = 0.306 + 81 = 81.31 m. = Initial ht.
of the balloon.
V^2 = Vo^2 + 2g*ho
V^2 = 0 + 19.6*81.31 = 1593.7
V = 39.9 m/s. = Final velocity.
4.9*0.25^2 = ho-81
0.306 = ho-81
ho = 0.306 + 81 = 81.31 m. = Initial ht.
of the balloon.
V^2 = Vo^2 + 2g*ho
V^2 = 0 + 19.6*81.31 = 1593.7
V = 39.9 m/s. = Final velocity.
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