Asked by TIM
A JAR CONTAINING 3 RED 4 BLUE AND 5 WHITE MARBLES WHATS THE CHANCE OF DRAWING FIRST A RED AND THEN WITHOUT REPLACEMENT A WHITE MARBLE?
Answers
Answered by
Damon
12 marbles
first draw 3/12 = 1/4
second draw 5/11
1/4 * 5/11 = 5/44
first draw 3/12 = 1/4
second draw 5/11
1/4 * 5/11 = 5/44
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