Asked by akshat

a father is 7times as old as his son .two years ago,the father was 13times as old as his son.how old tyey are now?
Answered by PsyDAG
Let x = son's age, and y = father's age

y = 7x

y-2 = 13(x-2) = 13x - 26

Substitute 7x for y in the second equation.

7x - 2 = 13x - 26

Solve for x, then put that value into first equation. Check by putting both values into the second equation.
Answered by shivam
28 year,4 year
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