Asked by Jeesha
NEED HELP On a flat battle ground, a catapult is used to launch a rock with a velocity of 25m/s at angle 30 degrees above the horizontal.?
Sketch the situation and decompose the initial velocity vector. WHat are the initial values for Vx and Vy?
Calculate the maximum height achieved by the rock
calculate the range
calculate the rock's velocity (magnitude and direction) 2.0 seconds after the launch
Sketch the situation and decompose the initial velocity vector. WHat are the initial values for Vx and Vy?
Calculate the maximum height achieved by the rock
calculate the range
calculate the rock's velocity (magnitude and direction) 2.0 seconds after the launch
Answers
Answered by
Henry
Vo = 25m/s[30o]
Vx = 25*cos30 = 21.65 m/s.
Vy = 25*sin30 = 12.50 m/s.
h=(V^2-Vy^2)/2g=(0-(12.5^2)/-19.6=7.97 m
Range = Vo^2*sin(2A)/g
Range = 25^2*sin(60)/9.8 = 55.23 m.
V=Vy + g*t = 12.50 + (-9.8*2) = -7.1m/s
21.65 - 7.1i=22.78m/s[-18.16o]=Velocity
2 seconds after the launch.
Note: The hor. component of velocity
does not change.
Vx = 25*cos30 = 21.65 m/s.
Vy = 25*sin30 = 12.50 m/s.
h=(V^2-Vy^2)/2g=(0-(12.5^2)/-19.6=7.97 m
Range = Vo^2*sin(2A)/g
Range = 25^2*sin(60)/9.8 = 55.23 m.
V=Vy + g*t = 12.50 + (-9.8*2) = -7.1m/s
21.65 - 7.1i=22.78m/s[-18.16o]=Velocity
2 seconds after the launch.
Note: The hor. component of velocity
does not change.
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