Asked by Kyan
The depth of water in a channel between two successive low tides can be modeled approximately using a quadratic function of time.
Low tide is at 11:45am and the next one also 0.46m is at 11:30pm. High tide is expected to be 2.16m
I need atleast 1 meter of water to launch the boat, preferably on a rising tide.
Recommend the times for launching my boat successfully.
Low tide is at 11:45am and the next one also 0.46m is at 11:30pm. High tide is expected to be 2.16m
I need atleast 1 meter of water to launch the boat, preferably on a rising tide.
Recommend the times for launching my boat successfully.
Answers
Answered by
Steve
let x be the time since midnight, and y be the water level. We have
y(11.75) = 0.46
y(23.50) = 0.46
the vertex is thus (17.625,2.16)
Now you have three points, so you can determine the parabola, and you want x where y=1.
y(11.75) = 0.46
y(23.50) = 0.46
the vertex is thus (17.625,2.16)
Now you have three points, so you can determine the parabola, and you want x where y=1.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.