Asked by jun gajetos
completing the square of x^2-3x-8=0
Answers
Answered by
Reiny
x^2-3x-8=0
x^2 - 3x = 8
x^2 - 3x + <b>9/4</b> = 8 + <b>9/4</b>
(x - 3/2)^2 = 41/4
x - 3/2 = ±√41/2
x = 3/2 ± √41/2 = (3 ±√41)/2
to find the term to be added to each side,
take 1/2 the coefficient of the x term , then square it
that is,
1/2 of 3 is 3/2, square it to get 9/4
x^2 - 3x = 8
x^2 - 3x + <b>9/4</b> = 8 + <b>9/4</b>
(x - 3/2)^2 = 41/4
x - 3/2 = ±√41/2
x = 3/2 ± √41/2 = (3 ±√41)/2
to find the term to be added to each side,
take 1/2 the coefficient of the x term , then square it
that is,
1/2 of 3 is 3/2, square it to get 9/4
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