Asked by Adam
If a bicycle wheel has traveled f/π feet after n complete revolutions, what is the length in feet of the diameter of the bicycle wheel?
A. f/nπ^2
B. π^2/fn
C. nf/π^2
D. nf/π^2
E. f/n
A. f/nπ^2
B. π^2/fn
C. nf/π^2
D. nf/π^2
E. f/n
Answers
Answered by
Reiny
n rotations = f/π ft
1 rotation = fπ/n ft
2πr = fπ/n
r = f/(2n) ft
diameter = 2r = f/n ft
1 rotation = fπ/n ft
2πr = fπ/n
r = f/(2n) ft
diameter = 2r = f/n ft
Answered by
Adam
thanks reiny
Answered by
Mr. Fourth
(F/pi) feet......in N rotation
?.............in 1 rotation
(F/ pi × N)feet
C= 2pi r
(F/ pi × N) = 2pi r
r = ( F/ 2(pi^2)N)
Answer....Dia = F/(pi N^2)
?.............in 1 rotation
(F/ pi × N)feet
C= 2pi r
(F/ pi × N) = 2pi r
r = ( F/ 2(pi^2)N)
Answer....Dia = F/(pi N^2)
Answered by
Ana
Emily's bicycle wheel has a diameter of 18 inches.
If the wheel makes 20 revolutions, approximately how far will the bicycle have traveled?
If the wheel makes 20 revolutions, approximately how far will the bicycle have traveled?
Answered by
alex
I need help on this too lol
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