Question

can someone help me with this word problem?

if a pro basketball player has a vertical leap of about 20 inches, what is his hangtime?
It is twice the time that it would take an object to fall 20 inches.

hangtime T = 2 * sqrt(2H/g)

H = 20"/(12 in/ft) = 1.6667 ft
g = 32.2 ft/s^2
T = 0.64 s

Related Questions

Here's a basketball problem: A 83.0 kg basketball player is running in the positive direction at 7.5... Problem 5) A player is standing on a basketball court. The angle of elevation from the foot of the p... Which of the following is a sentence fragment? Marina is a fast runner and a skilled basketball pla...