Asked by Soba
N2 (g) + 3 CL2 (g) ---> 2 NCL3 (g)
delta H = + 230 kj
-----
a) What mass of N2 would absorb 96.5 kj of heat as it reacts?
b) What volume of Cl2 at STP would be required to react with the N2 in part (a)?
delta H = + 230 kj
-----
a) What mass of N2 would absorb 96.5 kj of heat as it reacts?
b) What volume of Cl2 at STP would be required to react with the N2 in part (a)?
Answers
Answered by
bobpursley
I will be happy to critique your thinking.
Answered by
Soba
I don't know how to find mass with the enthalpy formula.
Answered by
DrBob222
Just rephrase the question.
If 230 kJ is delta H for 1 mol of N2, then how many mols would account for96.5 kJ
If 230 kJ is delta H for 1 mol of N2, then how many mols would account for96.5 kJ
Answered by
Soba
Thanks.