Asked by Lexmo
A sequence of numbers is called a Fibonacci-type sequence if each number (after for the first two) is the sum of the two numbers which precede it. For example, 1, 1, 2, 3, 5, 8 ... is a Fibonacci- type sequence. If 1985, x, y, 200 are four consecutive terms in a Fibonacci-type sequence, then x equals...
I don't know what they want. Please help.
I don't know what they want. Please help.
Answers
Answered by
Damon
y = 1985 + x
200 = x + y
so
200 = x + (1985+x)
back to you :)
200 = x + y
so
200 = x + (1985+x)
back to you :)
Answered by
Damon
By the way I suspect you mean 2000 not 200
Answered by
Steve
y = 1985+x
200 = x+y
Eliminate y and we have
1985+x = 200-x
2x = -1785
x = -892.5
and the numbers are
1985, -892.5, 1092.5, 200
200 = x+y
Eliminate y and we have
1985+x = 200-x
2x = -1785
x = -892.5
and the numbers are
1985, -892.5, 1092.5, 200
Answered by
Damon
It would help if that last date were odd :)
Answered by
Lexmo
It is 2000. But thanks!
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