Question

I just want some help checking my homework...

Question: A care travelling at a velocity of 42ms-1 suddenly loses engine power and slows at a constant rate. It comes to rest after 75 seconds.
a what is the acceleration during this time ?
b how far did the care travel before stopping ?


I used v== v + at ...and came up with - 0.56 m/s-2
and 1533 metres travelled ???

Help please. I have no idea if I am even remotely close to the right answer.

Answer 1

yes, 0 = 42 + 75 a
a = - .56

d = Vi t + .5 a t^2
d = 42(75) - .28(75)^2
= 3150 - 1575 = 1575

Answer 2

Thank you so much.... I got that wrong as didn't know whether to use the time... Got confused as the car was already moving .

Answer 3

You are welcome.