Question

A rock is thrown verticaly upward from ground level at time t = 0. At t = 1.65 s it passes the top of a tall tower, and 0.95 s later it reaches its maximum height. What is the height of the tower?

height = _______ m

First, find the initial velocity from the height of the tower:
Vf=vi - g time
where Vf is zero at the top.
solve for vi if t=1.65+.95

Then, knowing vi, solve for v at t=1.65

V=vi+ g t