Asked by Miley
ellipse with vertices of (6,3) and (6,-3) and a focus at (6,-2). this is what i have so far...
(x-6)^2+y^2/9=1. How do I get the value under (x-6)^2?
(x-6)^2+y^2/9=1. How do I get the value under (x-6)^2?
Answers
Answered by
Reiny
I answered this same question from you
http://www.jiskha.com/display.cgi?id=1212525764
http://www.jiskha.com/display.cgi?id=1212525764
Answered by
Miley
ya but you make no sense to me...no offense
Answered by
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