Asked by yvette

How many gallons of a 30% alcohol solution must be mixed with 60 gallons of a 14%
solution to obtain a solution that is 20% alcohol
Answered by Reiny
number of gallons of the 30% stuff --- x

.3x + .14(60) = .2(60+x)
30x + 14(60) = 20(60+x)
30x + 840 = 1200 +20x
10x = 360
x = 36

Answered by bobpursley
.3*V+.14*60=.2*(V+60)

solve for V
Answered by victoria
(2x2y2-3xy+4)(4xy2)
Answered by Anonymous
A mixture of alcohol and water contains a total of
52
52 oz of liquid. There are
13
13 oz of pure alcohol in the mixture. What percent of the mixture is​ water? What percent is​ alcohol?
Answered by Anonymous
A mixture of alcohol and water contains a total of
52 oz of liquid. There are

13 oz of pure alcohol in the mixture. What percent of the mixture is​ water? What percent is​ alcohol?
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