Asked by yvette
How many gallons of a 30% alcohol solution must be mixed with 60 gallons of a 14%
solution to obtain a solution that is 20% alcohol
solution to obtain a solution that is 20% alcohol
Answers
Answered by
Reiny
number of gallons of the 30% stuff --- x
.3x + .14(60) = .2(60+x)
30x + 14(60) = 20(60+x)
30x + 840 = 1200 +20x
10x = 360
x = 36
.3x + .14(60) = .2(60+x)
30x + 14(60) = 20(60+x)
30x + 840 = 1200 +20x
10x = 360
x = 36
Answered by
bobpursley
.3*V+.14*60=.2*(V+60)
solve for V
solve for V
Answered by
victoria
(2x2y2-3xy+4)(4xy2)
Answered by
Anonymous
A mixture of alcohol and water contains a total of
52
52 oz of liquid. There are
13
13 oz of pure alcohol in the mixture. What percent of the mixture is water? What percent is alcohol?
52
52 oz of liquid. There are
13
13 oz of pure alcohol in the mixture. What percent of the mixture is water? What percent is alcohol?
Answered by
Anonymous
A mixture of alcohol and water contains a total of
52 oz of liquid. There are
13 oz of pure alcohol in the mixture. What percent of the mixture is water? What percent is alcohol?
52 oz of liquid. There are
13 oz of pure alcohol in the mixture. What percent of the mixture is water? What percent is alcohol?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.