Question

How many gallons of a 30% alcohol solution must be mixed with 60 gallons of a 14%
solution to obtain a solution that is 20% alcohol

Answer 1

number of gallons of the 30% stuff --- x

.3x + .14(60) = .2(60+x)
30x + 14(60) = 20(60+x)
30x + 840 = 1200 +20x
10x = 360
x = 36

Answer 2

.3*V+.14*60=.2*(V+60)

solve for V

Answer 3

(2x2y2-3xy+4)(4xy2)

Answer 4

A mixture of alcohol and water contains a total of
52
52 oz of liquid. There are
13
13 oz of pure alcohol in the mixture. What percent of the mixture is​ water? What percent is​ alcohol?

Answer 5

A mixture of alcohol and water contains a total of
52 oz of liquid. There are

13 oz of pure alcohol in the mixture. What percent of the mixture is​ water? What percent is​ alcohol?