Question
a point mass starts moving in a straight line with a constant acceleration a .at a time t from beginning of motion ,the acceleration sign changes, without changing magnitude.determine the time t1from the beginning of motion in which the point of mass returns to initial point
Answers
Damon
LOL !!!
This is a trick question.
You know the answer.
It is exactly the same as throwing a ball straight up.
It takes just as long to go up
(0 = Vi - g t) so t = Vi/g
h = Vi t - (1/2) g t^2
as it takes to go down
0 = h - (1/2) g t^2
= Vi t - (1/2) g t^2 - (1/2) g t^2
t = Vi / g again going down
so t1 = 2 t
This is a trick question.
You know the answer.
It is exactly the same as throwing a ball straight up.
It takes just as long to go up
(0 = Vi - g t) so t = Vi/g
h = Vi t - (1/2) g t^2
as it takes to go down
0 = h - (1/2) g t^2
= Vi t - (1/2) g t^2 - (1/2) g t^2
t = Vi / g again going down
so t1 = 2 t