Asked by abhinendra
if the angle of elevation of a tower from a distance of 100m from its foot is 60*, then the height of tower is
Answers
Answered by
Reiny
height/100 = tan 60°
height = ..... ?
height = ..... ?
Answered by
roshni
20
Answered by
Sujal Kesharwani
Let the height of tower be AB=100m. The length of the shadow caste is 10√3m.
Therefore, angle of elevation of sun =?
Let the angle be Φ.
Therefore tanΦ= AB/BC
AB/BC=30/10√3
Therefore,
Tan Φ= 3/√3*√3/√3
Therefore tan Φ=√3
And we know that tan√3=60°.
Hence sun's elevation is 60°.
Therefore, angle of elevation of sun =?
Let the angle be Φ.
Therefore tanΦ= AB/BC
AB/BC=30/10√3
Therefore,
Tan Φ= 3/√3*√3/√3
Therefore tan Φ=√3
And we know that tan√3=60°.
Hence sun's elevation is 60°.
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