Asked by Tatiana
Express the following in term of sum (or difference)of logarithms:
log (10A)/(7B^2)
log (10A)/(7B^2)
Answers
Answered by
Reiny
log (10A)/(7B^2)
= log(10A) - log(7B^2)
= lof 10 + logA - (log7 + 2logB)
= 1 + logA - log7 - 2logB
= log(10A) - log(7B^2)
= lof 10 + logA - (log7 + 2logB)
= 1 + logA - log7 - 2logB
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