A male cheerleader does 2.25 kJ of work in lifting a 57.5 kg cheerleader 1.25 m off the ground during the half time show. The energy gained by the lifted cheerleader is __________ kJ.

Answer 1

force * distance in direction of force

= 57.5 * 9.81 * 1.25

= 705 Joules = 0.705 kJ

the rest of the 2.25 kJ is lost to heat and his own motion