Question

The HCF of 2 no. Is 1/28 of their LCM.The sum of the HCF and the LCM is 116.If one of the no. Is 16 , find the other.

Answer 1

H = (1/28)L
L = 28H

L + H = 116
28H + H = 116
29H = 116
H = 4
then L = 112

one number is 16
let the other number be 4x

then :
16 = 4*4
4x = 4*x
16x = 112
x = 7
and 4x= 28

The other number is 28


check:
16 = 2*2*2*2
28=2*2*7
LCF = 2*2 = 4
HCM = 2*2*2*2*7 = 112

is 4 equal to 1/28 of 112 ? yes
is 4+ 112 = 116 ? , YES

Answer 2

Its the right ans thank u for help

Answer 3

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