Asked by Susan

A 0.60 g sample consisting of only CaC2O4 & MgC2O4 is heated at 5000C, converting the two salts of CaCO3 and MgCO3 . The sample then weighs 0.465 g. If the sample had been heated to 9000C, where the products are CaO & MgO, what would the mixtures of oxides have weighed?
a) 0.12 g b) 0.21 g c) 0.252 g d) 0.3 g

Answers

Answered by DrBob222
There are several ways to do this and this method I'm showing you may be the longest but it's the first one I came up with. So here goes. This is a two equation problem and you solve the two equations simultaneously. Here are the steps.
1. Set up equations to calculate g CaC2O4 and g MgC2O4.
2. Then convert g CaC2O4 to g CaO
3. Convert g MgC2O4 to g MgO
4. Add g CaO + g MgO to find total. The correct answer is in the choices on your list.
Here are the equations.
Let X = mass CaC2O4
and Y = mass MgC2O4, then
-------------------
eqn 1 is X + Y = 0.60g
For eqn 2 you want to chemically convert X (which is CaC2O4) to CaCO3 and Y(which is MgC2O4) to MgCO3 because you know what the carbonates weigh.
MM stands for molar mass.
(MM CaCO3/MM CaC2O4)X + (MM MgCO3/MM MgC2O4)Y = 0.465g

Solve those two equations to find X and Y.
Then Xg CaCO3 can be converted to g CaO by (MM CaO/MM CaCO3)X = ?
Yg MgCO3 can be converted to g MgO by
(MM MgO/MM MgCO3)Y = ?
Then add g CaO to g MgO to find total.
You should obtain an answer VERY close to one of the choices.
Post your work if you get stuck.
Answered by Anonymous
0.3
Answered by Naincy
0.3
Answered by Abid kamal
0.3
Answered by BHUVNESH
0.252

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