Asked by Ria
What volumr 0.250 mol/L hydrochloric acid is neutralized by 1.50g of calcium hydroxide?
Answers
Answered by
bobpursley
Ca(OH)2 + 2 HCl >> CaCl2+ 2 H20
so moles HCl = 2*moles calcium hydroxide
= 2*1.50/74
VolumeHCl=MolesHCl/concentration=
=2*1.50/(74*.250)
so moles HCl = 2*moles calcium hydroxide
= 2*1.50/74
VolumeHCl=MolesHCl/concentration=
=2*1.50/(74*.250)
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