What volumr 0.250 mol/L hydrochloric acid is neutralized by 1.50g of calcium hydroxide?

Answer 1

Ca(OH)2 + 2 HCl >> CaCl2+ 2 H20

so moles HCl = 2*moles calcium hydroxide
= 2*1.50/74

VolumeHCl=MolesHCl/concentration=
=2*1.50/(74*.250)