A 90 kg boy jogs on a circular track with a radius of 40 m at 5 m / s. What is the boy’s angular momentum with respect to the center of the track?

Answer 1

L = I omega

I = m r^2 = 90 * 40^2

omega = v/r = 5 /40

so
L = 90 * 40^2 * 5 /40
= 90 * 200
= 18000