Asked by XXXY
A 90 kg boy jogs on a circular track with a radius of 40 m at 5 m / s. What is the boy’s angular momentum with respect to the center of the track?
Answers
Answered by
Damon
L = I omega
I = m r^2 = 90 * 40^2
omega = v/r = 5 /40
so
L = 90 * 40^2 * 5 /40
= 90 * 200
= 18000
I = m r^2 = 90 * 40^2
omega = v/r = 5 /40
so
L = 90 * 40^2 * 5 /40
= 90 * 200
= 18000
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