Asked by nialleen
The area of a rectangle is 2x^2+5x^2-x-6 cm. write a polynomial that represents its width if its length is 2x^2+ x-3.
Answers
Answered by
Reiny
You must have meant:
area is 2x^3+5x^2-x-6
if so, then it factors nicely into
(x-1)(x+2)(2x+3)
and the width of 2x^2 + x - 3 factors to (2x+3)(x-1)
then
(2x^3+5x^2-x-6) รท (2x^2+ x-3)
= (x-1)(x+2)(2x+3)/( (2x+3)(x-1) )
= x+2
or
you could do a long algebraic division as it stands and also get x+2
area is 2x^3+5x^2-x-6
if so, then it factors nicely into
(x-1)(x+2)(2x+3)
and the width of 2x^2 + x - 3 factors to (2x+3)(x-1)
then
(2x^3+5x^2-x-6) รท (2x^2+ x-3)
= (x-1)(x+2)(2x+3)/( (2x+3)(x-1) )
= x+2
or
you could do a long algebraic division as it stands and also get x+2
Answered by
nialleen
thanks a lot!
Answered by
Miguel calago
Math
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