I would say it is A
it simplifies to -x + 3 = 0 , which is linear and not quadratic.
If you force the issue and make it look like a quadratic, it would be
0x^2 - x + 3 = 0
so a=0 , b=-1 and c = 0
BUT, in the formula we are dividing by 2a which in this case would be dividing by zero,
an operation which is slightly frowned upon in mathematics.
Which of the following cannot be solved using the quadratic formula?
A.-3x^2-x+3=-3x^2
B. 0=x^2
C. 0=2x^2-1
D. x^2+3x-2=4x^2-5x-1
Is it C?
1 answer