Asked by Anonymous
What mass of cesium chloride must be added to 0.570 L water to produce a 0.375 m solution?
Answers
Answered by
DrBob222
m = mols/kg solvent
0.375 = mols/0.570 = ?
Solve for mols.
Then mol = grams/molar mass
You have mol and molar mass, solve for grams.
0.375 = mols/0.570 = ?
Solve for mols.
Then mol = grams/molar mass
You have mol and molar mass, solve for grams.
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