Asked by ashraf

how are you going to prepare the follwoing phosphate solution which is used in many cell culture medium? 12 liters ;PH 7.4; 0.9%WT (total salts weight is 9.00 grams in one liter)
How many grams of what acid?
how many grams of the conjugate base?

Answers

Answered by DrBob222
You have two equations.
pH = pK2for H3PO4 + log (base)/(acid)
7.4 = pK2 + log b/a
solve for b/a and that's one equation.
The second one is
acid + base = molarity of solution.
Since you want 9g/L and that x 12L you want that many grams in the 12L. Convert that to M.
Then solve the two equation simultaneously for acid and for base; finally convert those to grams.
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