Ask a New Question

Question

what are the excluded values?
y+5/y^2+4y-32
11 years ago

Answers

becky
the answer choices for this question is.
y = -5 and 4
y = 5 and 32
y = 4 and -8
none of the above
11 years ago
Reiny
again, you should type it as

(y+5)/(x^2 + 4y - 32) , the way you have it, the only division is 5/y^2

= (y+5)/((y+8)(y-4))

so which values would make the denominator zero ?
11 years ago

Related Questions

what values are excluded from the domain of the function f(x)= x-5/x? what is the excluded values for the fraction a --- 3-2a What are the excluded values? 2/x(x-3) What are the excluded values of (8x^3 y) / (27xy^5) simplified: 8x^2/27y^4 What are the excluded values of the function? y equals 3 over the quantity 4 times x plus 64... What are the excluded values for this quotient? x^3-4/x^3-9 divided by 3x^3+9x/x^3+6x+9 A. 0,3... What are the excluded values of the function? y equals 5 over the quantity 6 times x plus 72 What are the excluded values of the function? y equals Start Fraction 5 over 6 x minus 72 End Fracti...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use