could someone check my answers to see if they are right?
Balance the following equation and give the value of the stoichiometric coefficient marked with a question mark.
6 KNO3+ _ S + ? H2O _ H2SO4+ _ N2+ _ K2SO4
answer:6KNO3 + 5S + 2H2O --> 3 K2SO4 + 3N2 + 2H2SO3
42 KMnO4+ _ C3H5(OH)3 ? CO2+ _ Mn2O3+ _ K2CO3+ _ H2O
answer:14 KMnO4 + 4 C3H5(OH)3 --> 7 K2CO3 + 7 Mn2O3 + 5 CO2 + 16 H2O
For the first one, there are 20 O's on the left and only 18 O's on the right.
The second one is correct
would you please check these?
4. 42 KMnO4 + ? C3H5(OH)3 _ CO2+ _ Mn2O3+ _ K2CO3+ _ H2O
answer:
14 KMnO4 + 4 C3H5(OH)3 --> 7 K2CO3 + 7 Mn2O3 + 5 CO2 + 16 H2O
5. 6 KNO3+ _ S + _ H2O ? H2SO4+ _ N2+ _ K2SO4
answer:6KNO3 + 5S + 2H2O „³ 3 K2SO4 + 3N2 + 2H2SO3
6. 42 KMnO4 + ? C3H5(OH)3 _ CO2+ _ Mn2O3+ _ K2CO3+ _ H2O
answer:14 KMnO4 + 4 C3H5(OH)3 --> 7 K2CO3 + 7 Mn2O3 + 5 CO2 + 16 H2O
It is right, you misstyped H2SO4 in the product.
#1 doesn't balance because you made a typo on the right side. The equation to be balanced has H2SO4 while in the rewrite you have H2SO3. Using 2H2SO4 will get the other two Os you need on the right.
I'm confused..i am getting different answers from different people. here is the whole assignment..please check
1. 48 KNO3+ _ C 12 H22O11 ? CO2+ _ N2+ _ K2CO3+ _ H2O
a. 12
b. 24 s
c. 36
d. 48
The reaction is
96 KNO3 + 10 C12H22O11 --> 48 K2CO3 + 72 CO2 + 110 H2O + 48 N2
So the answer is 72 /2 = 36 ANSWER IS C FOR THE CO2
Do I need to use smaller numbers?
2. 6 KNO3+ _ S + ? H2O _ H2SO4+ _ N2+ _ K2SO4
a. 2
b. 4
c. 6
d. 8
The balanced reaction is
6KNO3 + 5S + 2H2O „³ 3 H2SO4 + 3N2 + 2H2SO3
The answer to H2O is 2 (answer A)
R3. 42 KMnO4+ _ C3H5(OH)3 ? CO2+ _ Mn2O3+ _ K2CO3+ _ H2O
a. 5
b. 15
c. 18
d. 7
The reaction is
14 KMnO4 + 4 C3H5(OH)3 --> 7 K2CO3 + 7 Mn2O3 + 5 CO2 + 16 H2O
The answer for CO2 is 5 X 3 =15 (answer B)
4. 42 KMnO4 + ? C3H5(OH)3 _ CO2+ _ Mn2O3+ _ K2CO3+ _ H2O
a. 6
b. 7
c. 8
d. 12
The reaction is
14 KMnO4 + 4 C3H5(OH)3 --> 7 K2CO3 + 7 Mn2O3 + 5 CO2 + 16 H2O
answer is 3X4 =12 (answer D)
5. 6 KNO3+ _ S + _ H2O ? H2SO4+ _ N2+ _ K2SO4
a. 2
b. 4
c. 6
d. 12
The balanced reaction is
6KNO3 + 5S + 2H2O „³ 3 H2SO4 + 3N2 + 2K2SO4
so for 6 KNO3 the answer to H2SO3 is 2 (answer A)
6. 42 KMnO4 + ? C3H5(OH)3 _ CO2+ _ Mn2O3+ _ K2CO3+ _ H2O
a. 6
b. 7
c. 12
d. 42
The balanced reaction is
14 KMnO4 + 4 C3H5(OH)3 --> 7 K2CO3 + 7 Mn2O3 + 5 CO2 + 16 H2O
answer is 3X4 =12 (answer C)
7. 12 C3H5(OH)3 + ? KMnO4 _ CO2+ _ Mn2O3+ _ K2CO3+ _ H2O
a. 6
b. 12
c. 8
d. 42
The balanced reaction is
14 KMnO4 + 4 C3H5(OH)3 --> 7 K2CO3 + 7 Mn2O3 + 5 CO2 + 16 H2O
answer is 14 X 3 = 42 (answer D)
8. 5 S + _ KNO3+ _ H2O _ H2SO4 + ? N2+ _ K2SO4
a. 3
b. 6
c. 10
d. 15
The balanced reaction is
6KNO3 + 5S + 2H2O „³ 3 K2SO4 + 3N2 + 2H2SO3
the coefficient for N2 is 3 (answer A)
9. 5 C12H22O11 + ? KNO3 _ CO2+ _ N2+ _ K2CO3+ _ H2O
a. 5
b. 15
c. 24
d. 48
The balanced reaction is
96 KNO3 + 10 C12H22O11 --> 48 K2CO3 + 72 CO2 + 110 H2O + 48 N2
So the answer for KNO3 is 48 (answer D)
10. 48 KNO3 + ? C12H22O11 _ CO2+ _ N2+ _ K2CO3+ _ H2O
a. 5
b. 7
c. 6
d. 12
The balanced reaction is
96 KNO3 + 10 C12H22O11 --> 48 K2CO3 + 72 CO2 + 110 H2O + 48 N2
So the answer for the C12H22O11 is 5 (answer A)
Whats an alloy?
2 answers
1 answer