Asked by Moyamé
A body which has three forces acting on it is in equilibrium. One force is 3N to the North, and another is 4N to the west. Find the magnitude and the direction of the third force. Show the vector diagram.
Answers
Answered by
bobpursley
The sum of the forces=zero
3N+4W+ ? =0
?force= -3N-4W
magnitude= sqrt(9+16)
direction SE, draw the triangle, find the angle.
3N+4W+ ? =0
?force= -3N-4W
magnitude= sqrt(9+16)
direction SE, draw the triangle, find the angle.
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