If there were x adult tickets, then there were 340-x students. So,
5.00x + 3.50(340-x) = 1535.00
Now just solve for x...
5.00x + 3.50(340-x) = 1535.00
Now just solve for x...
According to the given information, the total number of tickets sold was 340:
A + S = 340
The cost of each adult ticket was $5.00, and the cost of each student ticket was $3.50. The total revenue from ticket sales was $1535.00:
5A + 3.50S = 1535
We can solve this system of equations to find the values of A and S. Let's use the substitution method:
From the first equation, we can express A in terms of S:
A = 340 - S
Substituting this value in the second equation, we have:
5(340 - S) + 3.50S = 1535
Simplifying, we get:
1700 - 5S + 3.50S = 1535
-1.5S = 1535 - 1700
-1.5S = -165
Solving for S, we have:
S = -165 / -1.5
S = 110
Now, substituting this value back into the first equation:
A + 110 = 340
A = 340 - 110
A = 230
Therefore, 230 adult tickets were sold.
We are told that the total number of tickets sold is 340, so our first equation is:
A + S = 340
We are also given that the total revenue from ticket sales is $1535.00. Since adult tickets cost $5.00 and student tickets cost $3.50, we can write our second equation as:
5A + 3.5S = 1535
Now we can solve this system of equations to find the values of A and S.
One way to solve this system is by substitution. Rearranging the first equation, we have:
A = 340 - S
Substituting this expression for A into the second equation, we have:
5(340 - S) + 3.5S = 1535
Expanding and simplifying, we have:
1700 - 5S + 3.5S = 1535
-1.5S = -165
S = 110
Substituting this value of S back into the first equation, we find:
A + 110 = 340
A = 230
Therefore, 230 adult tickets were sold.