Asked by Chen Sam
Rufus is in charge of lighting a play. Half the lights he uses are white. Of the remaining lights, 1/3 have red filters, and 4 have blue filters. The 10 lights left have yellow filters. How many lights does Rufus use for the play?
Answers
Answered by
Anonymous
42. You split the total in half, one half is white the other half has 1/3 red filters meaning the 4 blue filters and 10 yellow filters represent 2/3. We now know that 1/3 of half of the lights is 7. 21 is one half of the lights 2 halves is 42.
Answered by
Reiny
Using proper algebra:
number of lights --- x
white = x/2
red = (1/3)(x/2) = x/6
blue = 4
yellow = 10
x/2 + x/6 + 4 + 10 = x
times 6
3x + x + 6(14) = 6x
84 = 2x
x = 42
42 lights in total
check:
whites = 21
leaves 21
red = (1/3)of 21 = 7
sum = 21 whites + 7 red + 4 blue + 10 yello
= 42
number of lights --- x
white = x/2
red = (1/3)(x/2) = x/6
blue = 4
yellow = 10
x/2 + x/6 + 4 + 10 = x
times 6
3x + x + 6(14) = 6x
84 = 2x
x = 42
42 lights in total
check:
whites = 21
leaves 21
red = (1/3)of 21 = 7
sum = 21 whites + 7 red + 4 blue + 10 yello
= 42
Answered by
Samm
The answer is 67
Answered by
Leo Jiang
The answer is 42 Samm
Answered by
Hi
You just do:
1/2 x 1/3 = 1/6
1/2 = 3/6
3/6 + 1/6 = 4/6
6/6 - 4/6 = 2/6
2/6 = 14/x
x = 42
1/2 x 1/3 = 1/6
1/2 = 3/6
3/6 + 1/6 = 4/6
6/6 - 4/6 = 2/6
2/6 = 14/x
x = 42
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