Asked by Francis

9x^2 6xy 4y^2 is a factor of 27x^3 - 8y^3, find the other factor.
Answered by Steve
27x^3-8y^3 is the difference of two cubes: (3x)^3 - (2y)^3

So, it factors as (3x-2y)(9x^2+6xy+4y^2)
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