Asked by soumitra

find the value...

lim (tan 2x- x)/(3x- sin x)
x>0
Answered by soumitra
plz answer without L hospital rule
Answered by Steve
using the well-known proofs that sinx -> x, we can conclude that

tan2x -> 2x

so we have the limit as

(2x-x)/(3x-x) = 1/2
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