A power station with an efficiency of 0.35 generates 10^8 W of electric power and dissipates 1.86 ✕ 10^8 W of thermal energy to the cooling water that flows through it. Knowing the specific heat of water in SI units is 4184 J/kg°C, calculate how many kilograms of water flow through the plant each second if the water is heated through 2 degrees Celsius.

asked by boy

10 years ago

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1 answer

energy to water per second = 1.86*10^8 Joules

Kg water per second heated = m

1.86*10^8 = 4184 * m * 2

answered by Damon

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Question

A power station with an efficiency of 0.35 generates 10^8 W of electric power and dissipates 1.86 ✕ 10^8 W of thermal energy to the cooling water that flows through it. Knowing the specific heat of water in SI units is 4184 J/kg°C, calculate how many kilograms of water flow through the plant each second if the water is heated through 2 degrees Celsius.

1 answer

energy to water per second = 1.86*10^8 Joules

Kg water per second heated = m

1.86*10^8 = 4184 * m * 2

Damon · Answer

energy to water per second = 1.86*10^8 Joules Kg water per second heated = m 1.86*10^8 = 4184 * m * 2