Asked by Junior
Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10%. The second car depreciates at an annual rate of 15%. What is the approximate difference in the ages of the two cars?
1.7 ears
2.0 years
3.1 years
or 5.0 years
1.7 ears
2.0 years
3.1 years
or 5.0 years
Answers
Answered by
Steve
log<sub>0.90</sub>0.6 - log<sub>0.85</sub>0.6 = 1.7
or, since you probably don't have a button for log<sub>0.9</sub>x,
log(0.6)/log(0.9) - log(0.6)/log(0.85)
or even
log(0.6)(1/log(0.9)-1/log(0.85))
or, since you probably don't have a button for log<sub>0.9</sub>x,
log(0.6)/log(0.9) - log(0.6)/log(0.85)
or even
log(0.6)(1/log(0.9)-1/log(0.85))
Answered by
Anonymous
Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10%. The second car depreciates at an annual rate of 15%. What is the approximate difference in the ages of the two cars?
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