Asked by sharon
                y = -7x - 9,  -3y = 21x + 7
without graphing, tell whether the graphs of each pair of equations are perpendicular.
            
            
        without graphing, tell whether the graphs of each pair of equations are perpendicular.
Answers
                    Answered by
            Barry
            
    Dear sharon,
the first equation
y = -7x - 9
slope= -7
y-intercept= -9
the second equation
-3y = 21x + 7
y = -7x -(7/3)
slope= -7
y-intercept= -(7/3)
To determine whether the two lines are perpendicular
slope of equation 1 X slope of equation 2 must be -1.
But in this case,
slope of equation 1 X slope of equation 2 = 49 instead of -1
so the two lines are not perpendicular.
(However, slope of equation 1 = slope of equation 2 and the y-intercept of the two equations are not the same, so we know that the two lines are parallel to each other.)
Hope it helps!
Wishing you the best of luck,
Barry
    
the first equation
y = -7x - 9
slope= -7
y-intercept= -9
the second equation
-3y = 21x + 7
y = -7x -(7/3)
slope= -7
y-intercept= -(7/3)
To determine whether the two lines are perpendicular
slope of equation 1 X slope of equation 2 must be -1.
But in this case,
slope of equation 1 X slope of equation 2 = 49 instead of -1
so the two lines are not perpendicular.
(However, slope of equation 1 = slope of equation 2 and the y-intercept of the two equations are not the same, so we know that the two lines are parallel to each other.)
Hope it helps!
Wishing you the best of luck,
Barry
                    Answered by
            Steve
            
    the slopes are the same, so they are either parallel or the same line.
If you multiply the 1st by -3, the constant term is different from 7, so the lines are parallel.
    
If you multiply the 1st by -3, the constant term is different from 7, so the lines are parallel.
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