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Due to a strong wind from the west of 65 km/h, a plane ends up traveling 330 km/h [W 15 S] relative to the ground. What was the magnitude of the velocity of the plane relative to the air in km/h?

1 answer

330 cos 15 = Vwest - 65

330 sin 15 = Vsouth

so
Vwest = 383.7 km/h

Vsouth = 85.4 km/hr

Vplane = sqrt (383.7^2+85.4*2)

tan angle south of west = 85.4/383.7
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