Question
Due to a strong wind from the west of 65 km/h, a plane ends up traveling 330 km/h [W 15 S] relative to the ground. What was the magnitude of the velocity of the plane relative to the air in km/h?
Answers
Damon
330 cos 15 = Vwest - 65
330 sin 15 = Vsouth
so
Vwest = 383.7 km/h
Vsouth = 85.4 km/hr
Vplane = sqrt (383.7^2+85.4*2)
tan angle south of west = 85.4/383.7
330 sin 15 = Vsouth
so
Vwest = 383.7 km/h
Vsouth = 85.4 km/hr
Vplane = sqrt (383.7^2+85.4*2)
tan angle south of west = 85.4/383.7