Asked by karan

The equilibrium constant of the reaction CH3COOH (l)+C2H5OH (l)=CH3COOC2H5+H2O is 4.if one mole of each of acetic acid and ethyl alcohol are heated in presence of little concentrated H2SO4 at equilibrium the amount of ester present is?

Answered by DrBob222
I've shortened the equation. HAc is acetic acid, RCH2OH is the alcohol and RCOOR is the ester.
..........HAc + RCH2OH --> RCOOR + H2O
I.........1.0....1.0........0.......0
C..........-x.....x.........x.......x
E.........1.0-x..1.0-x......x.......x

Substitute the E line into Kc and solve.
Answered by Shadi
Ester present is 2 moles, because first of all,

4=x^2/(1-x)(1-x) solve it and it will turn out to be this
3x^2-8x+4
x=2

so the ester is 2 =
Answered by Anonymous
It comes out 2 and 2/3 and we have to take 2/3
Answered by Anonymous
why not 2
Answered by Bob
Because (1-2) would be negative and concentration cannot be negative
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