Asked by Brooklynne
during an effusion experiment, oxygen gas passed through a tiny hole 2.5 times faster than the same number of moles in another gas under the same conditions. What is the molar mass of the unknown gas?
Answers
Answered by
DrBob222
The easy way to do these is to assume some convenient number for the rate of effusion. The number 1 is an easy one to use.
unknown gas rate = 1L/min
oxygen gas rate = 2.5*1L/min = 2.5 L/min
(rate O2/rate unk) = swrt(MMunk/MMO2)
(2.5/1) = sqrt(MMunk/32)
Solve for molar mass (MM) unk.
unknown gas rate = 1L/min
oxygen gas rate = 2.5*1L/min = 2.5 L/min
(rate O2/rate unk) = swrt(MMunk/MMO2)
(2.5/1) = sqrt(MMunk/32)
Solve for molar mass (MM) unk.
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