Asked by samantha
An object with mass 110 kg moved in outer space. When it was at location < 11, -35, -7 > its speed was 17.5 m/s. A single constant force < 230, 420, -230 > N acted on the object while the object moved to location < 16, -41, -13 > m. What is the speed of the object at this final location?
final speed =
final speed =
Answers
Answered by
Steve
The force was applied in the direction
<16,-41,-13> - <11,-35,-7>
F=ma gives you the magnitude of the acceleration
Then just figure t to cover the given distance, and
v = v0 + at to get the final velocity.
<16,-41,-13> - <11,-35,-7>
F=ma gives you the magnitude of the acceleration
Then just figure t to cover the given distance, and
v = v0 + at to get the final velocity.
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