Ask a New Question

Asked by ken

A sample of peanut oil weighing 2g is added to 25ml of 0.4M koh. After saponification is complete, 8.5ml of 0.28M hes04 is needed to neutralize excess of koh. Saponification number of peanut oil

Thank for all tutors for your help.

Pls solve it for me step by step for me.
The answer 146.75
11 years ago

Answers

Answered by DrBob222
See your post below.
11 years ago

Related Questions

A sample of gas weighing 9.0 (g) at a pressure of 1 atm occupies a volume of 12.3 L. If the pressure... A sample weighing 3.064 g is a mixture of Fe2O3 (molar mass = 159.69) and Al2O3 (molar mass = 101.96... A sample of iron weighing 15.0 g was heated with potassium chlorate (KClO3) in an evacuated containe... A sample of peanut oil weighing 2g is added to 25ml of 0.4M koh. After saponification is complete,... A sample of peanut oil weighing 2g is added to 25ml of 0.4M koh. After saponification is complete, 8... A 56 g sample of peanut oil has a volume of 60.9 cm^3. Calculate the density of the peanut oil. 1. A sample weighing 1.30 mg was analyzed to determine the concentration of a certain compound (FW =... a sample of air weighing 1.32 * 103 n is confined in a room measuring 9.5m * 5.0m * 2.0m . calculate... A sample of air weighing 1.32×10³N is con firmed in a room measuring 9.5m×2.0m calculate the density... A sample of air weighing 1.32 x 103N is confirmed in a room measuring 1.5cm x 5.0 x 2.0cm calculate...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use