Z = (score-mean)/SD
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability (±.415) related to the Z scores. Insert Z values into the above equation.
The mean score on the first calculus exam was 55%. The standard deviation was 7%. Find the smallest interval about the mean that must contain at least 83% of the scores.
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2 answers
did u figure this out yet....? ahhhh
1 answer