Asked by jack higgins

The mean score on the first calculus exam was 55%. The standard deviation was 7%. Find the smallest interval about the mean that must contain at least 83% of the scores.

heeellllppppp

Answers

Answered by PsyDAG
Z = (score-mean)/SD

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability (±.415) related to the Z scores. Insert Z values into the above equation.
Answered by jayyyme
did u figure this out yet....? ahhhh
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions