Asked by Liz

How would I answer number 3?

1. A sumo wrestler originally jumps 10 cm above a trampoline but has the same total energy of a small ball that was 200 cm higher than the trampoline. What causes this equivalency?

2. If a 40 kg gymnast and a 400 kg sumo wrestler each dropped from 1 m above the trampoline, find the final position of each athlete. Assume the trampoline is a simple spring obeying Hooke's law with a k value of 12 000 N/m.

3. Real world trampolines lose energy since they are damped springs with much internal friction. How much energy does the sumo wrestler lose on each bounce in this situation

Answers

Answered by Damon
I did #1

#2
potential energy lost = m g h
potential energy gained = (1/2) k x^2

for 40 kg

40 * 9.81 * (1+x) = (1/2)(12,000) x^2

solve quadratic for x

#3
I have no idea because you did not tell me ratio of bounces
Answered by Anonymous
how do you do number 1
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions