Ask a New Question

Question

This is giving me a lot of trouble.
Factoring Differences of Squares
Factor Completely
98-8w^2
and can you explain how you got the common factor if there is one please
11 years ago

Answers

Steve
just recall that a^2-b^2 = (a-b)(a+b)

So, first, make sure that both terms are perfect squares.

In this case, they are not. However, if you factor out a 2, you have

2(49-4w^2)
49 is 7^2 and 4w^2 = (2w)^2. So, we now have

2(7-2w)(7+2w)
11 years ago

Related Questions

For some reason I'm having trouble posting the question. Here it is hopefully. Q2.CDMA Communicat... Hello, I'm having a bit of trouble with two questions: 1. Phoenecia deposits $300 into a simple i... I'm having a little bit of trouble with Adventures of Huckleberry Finn I don't believe you ha... Hello, I am having some trouble trying to reduce a benzene ring with a H3C-C=N-NH2 substituent, t... Hello! I'm having a bit of trouble trying to solve this physics problem. I'm not sure which equation... Hiiiii I'm Having a lot of trouble solving this problem. I was wondering if anyone could please help... I'm having a little bit of trouble of figuring what words to use since they don't have any word opti... Many would-be runners have trouble getting motivated. They may become bored with the repetitive natu... What is the definition of "troubadour?"(3 points) Responses refers to a medieval poet-musician w...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use