Asked by MissPatte

This is giving me a lot of trouble.
Factoring Differences of Squares
Factor Completely
98-8w^2
and can you explain how you got the common factor if there is one please

Answers

Answered by Steve
just recall that a^2-b^2 = (a-b)(a+b)

So, first, make sure that both terms are perfect squares.

In this case, they are not. However, if you factor out a 2, you have

2(49-4w^2)
49 is 7^2 and 4w^2 = (2w)^2. So, we now have

2(7-2w)(7+2w)
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