Asked by Marcus
I am sorry I didn't complete the problem
Here is the question:
Doris invested some money at 7% and some money at 8%. She invested $6,000 more at 8% than she did at 7%. Her yearly total from the two investments was $7.80. How much did Doris invest at each rate?
(A)$2,000 at7% and $8,000 at 8%
(B)$3,000 at 7% and $7,000 at 8%
(C)$1,500 at 7% and $9,000 at 8%
(D)$4,000 At 7% and $4,000 at 8%
Here is the question:
Doris invested some money at 7% and some money at 8%. She invested $6,000 more at 8% than she did at 7%. Her yearly total from the two investments was $7.80. How much did Doris invest at each rate?
(A)$2,000 at7% and $8,000 at 8%
(B)$3,000 at 7% and $7,000 at 8%
(C)$1,500 at 7% and $9,000 at 8%
(D)$4,000 At 7% and $4,000 at 8%
Answers
Answered by
Steve
if x at 7%, then
.07x + .08(x+6000) = 7.80
Fix the interest amount and solve for x. And pay more attention to what you type.
.07x + .08(x+6000) = 7.80
Fix the interest amount and solve for x. And pay more attention to what you type.
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