Asked by Anonymous
A car traveling at2.24m/s skids and stops in
2.55s determine the skidding distance of car
2.55s determine the skidding distance of car
Answers
Answered by
MathMate
<b>Acceleration</b>
= (vf-vi)/t
= -2.24/2.55
= -0.8784 m/s
<b>Δx = vi*t + (1/2)at²</b>
=2.24(2.55)+(1/2)(-0.8784)(2.55²)
= 2.85 m
= (vf-vi)/t
= -2.24/2.55
= -0.8784 m/s
<b>Δx = vi*t + (1/2)at²</b>
=2.24(2.55)+(1/2)(-0.8784)(2.55²)
= 2.85 m
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