Asked by John
A missile is fired from a launcher with an initial velocity of 250 m/s at a target located 500 m above the launcher and at a horizontal distance of 3000 m. Determine the following:
i) The possible firing angles required to hit the target.
ii) The maximum height reached for all possible angles.
iii) The time taken for the missile to hit the target for all possible firing angles.
i) The possible firing angles required to hit the target.
ii) The maximum height reached for all possible angles.
iii) The time taken for the missile to hit the target for all possible firing angles.
Answers
Answered by
Steve
(i) the range for angle θ is
R = v^2/g sin2θ
(ii) Naturally max height is reached at θ = 45°
(iii) given the range, and that horizontal velocity is constant, getting t is easy.
So, what do you get?
R = v^2/g sin2θ
(ii) Naturally max height is reached at θ = 45°
(iii) given the range, and that horizontal velocity is constant, getting t is easy.
So, what do you get?
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