Question

I am familiar with finding the vertex of a polynomial but I don't know how to solve this equation.
Give the vertex of x^2+9
can you please explain in steps?
Thank you.

Answer 1

An equation requires an equal sign.

Answer 2

If you mean

y = x^2+9

you can see that since x^2 can never be less than zero, the vertex is at x=0. Since y=9 there, the vertex is at (0,9)

Or, recalling that the vertex of

y = (x-h)^2 + k

is at (h,k), note that we have h=0 and k=9.