Question
what was the initial velocity of a race car traveling down a long straight track if it accelerates at 5.79m/s^2 and ends up going 163km/h in a time of 3.60 seconds?
Answers
Conversion factor:
<b>1 m/s = 3.6 km/h</b>
Δv=(vf-vi)=vi+aΔt
163 km/h = 163/3.6 = 45.28 m/s
45.28=vi+5.79*3.6
vi = 24.4 m/s = 88.0 km/h
<b>1 m/s = 3.6 km/h</b>
Δv=(vf-vi)=vi+aΔt
163 km/h = 163/3.6 = 45.28 m/s
45.28=vi+5.79*3.6
vi = 24.4 m/s = 88.0 km/h